Question

You have 2.28 moles of NH3. How many moles of NO are needed to react with this amount of ammonia? How many moles of each of the products will be formed?

Answer 1

To react with 2.28 moles of NH3, you would need 2.85 moles of NO. The reaction would also produce 3.42 moles of H2O and 2.28 moles of N2.

Step-by-step explanation:

To determine how many moles of NO are needed to react with 2.28 moles of NH3, we need to look at the balanced chemical equation for the reaction between NH3 and NO.

The balanced equation is: 4 NH3 + 5 NO -> 6 H2O + 4 N2

From the balanced equation, we can see that for every 4 moles of NH3, 5 moles of NO are needed. So, if we have 2.28 moles of NH3, we can set up a proportion to calculate the moles of NO needed:

(5 moles NO) / (4 moles NH3) = (x moles NO) / (2.28 moles NH3)

Solving this proportion gives us x = 2.85 moles NO.

To determine the moles of each product formed, we can use the mole ratios from the balanced equation. For every 4 moles of NH3, 6 moles of H2O and 4 moles of N2 are formed. So, if we have 2.28 moles of NH3, we can calculate the moles of H2O and N2 formed using these ratios:

(6 moles H2O) / (4 moles NH3) = (x moles H2O) / (2.28 moles NH3)

Solving this proportion gives us x = 3.42 moles H2O.

(4 moles N2) / (4 moles NH3) = (x moles N2) / (2.28 moles NH3)

Solving this proportion gives us x = 2.28 moles N2.