Final answer:
The probability that a normally distributed random variable X with mean 50 and standard deviation 7 is greater than 35 is approximately 1.66%.
Step-by-step explanation:
The student has asked to compute the probability P(X>35) for a normally distributed random variable X with a mean of 50 and a standard deviation of 7. To find this probability, we can use a standard normal distribution table, a calculator, or statistical software that can compute probabilities for normal distributions.
First, we need to convert the random variable X to the standard normal variable Z:
Z = (X - mean) / standard deviation
Z = (35 - 50) / 7 = -15 / 7 ≈ -2.14
Now we find P(Z > -2.14). The standard normal distribution is symmetric about the mean (which is 0 for Z), so we can calculate P(Z < 2.14) and subtract this from 1 to get the desired probability:
P(X>35) = 1 - P(Z < 2.14)
Using a Z-table or calculator, we find that P(Z < 2.14) is approximately 0.9834. Therefore,
P(X>35) ≈ 1 - 0.9834 = 0.0166
The probability that X is greater than 35 is approximately 1.66%.