Question

Translate to a system of equations:

Twice a number plus three times a second number is negative one. The first number plus four times the second number is two.



Call the first number m and the second number n.

Answer 1

The system of equations is:

`2m + 3n = -1 \\m + 4n = 2\end{cases}`

Let's represent the unknown numbers as m and n.

The given information can be translated into a system of equations as follows:

Twice a number plus three times a second number is negative one:

2m+3n=−1

The first number plus four times the second number is two:

m+4n=2

So, the system of equations is:

`2m + 3n = -1 \\m + 4n = 2\end{cases}`