Question

An object with a net charge of 29 microC is placed in a uniform electric field of 628 N/C directed vertically. What’s the mass of this object if the acceleration of gravity is 9.81 m/s^2?

Answer 1

To find the mass, we need to use the formula F = ma, where F is the force, m is the mass, and a is the acceleration. Here, the force is the electric force, which is given by F = qE, where q is the charge and E is the electric field. So, we have qE = ma. Rearranging for m gives m = qE/a. Plugging in the given values (remember to convert the charge from microCoulombs to Coulombs by multiplying by 10^-6), we get m = (29 x 10^-6 C * 628 N/C) / 9.81 m/s^2.

Step-by-step explanation: