Final answer:
The vertices of the midsegment triangle of ΔXYZ with vertices X(-5, -2), Y(-3, 4), and Z(3, 0) are found at (-4, 1) for XY, (0, 2) for YZ, and (-1, -1) for XZ by calculating the midpoints of each side of the triangle.
Step-by-step explanation:
To find the coordinates of the vertices of the midsegment triangle of ΔXYZ, we need to calculate the midpoints of each side of the triangle. The midsegment of a triangle connects the midpoints of two sides and is parallel to the third side.
- Vertex on XY: We calculate the midpoint between X(-5, -2) and Y(-3, 4). Using the midpoint formula, which is ((x1 + x2)/2, (y1 + y2)/2), we get the following coordinates: ((-5 - 3)/2, (-2 + 4)/2), which simplifies to (-4, 1).
- Vertex on YZ: For the midpoint between Y(-3, 4) and Z(3, 0), apply the midpoint formula to get ((-3 + 3)/2, (4 + 0)/2), resulting in (0, 2).
- Vertex on XZ: The midpoint between X(-5, -2) and Z(3, 0) is found with the formula, resulting in ((-5 + 3)/2, (-2 + 0)/2), which is (-1, -1).
Therefore, the coordinates of the vertices of the midsegment triangle are (-4, 1), (0, 2), and (-1, -1).