Question

19. Two monkeys are connected by a rope of negligible mass, which passes over a pulley. Friction in the pulley is negligible. One monkey has a mass of 20.0 kg, while the other has an unknown mass, m, as shown.

a. Assuming the acceleration is 0.467m/s2, what is the tension in the rope?

Answer 1

To find the tension in the rope, we can use Newton's second law. The tension in the rope is equal to the net force acting on the system, which is equal to the product of the mass and acceleration.

Step-by-step explanation:

In this problem, we have two monkeys connected by a rope over a pulley. One monkey has a mass of 20.0 kg and the other monkey has an unknown mass, denoted as m. We are given that the acceleration of the system is 0.467 m/s².

To find the tension in the rope, we can use Newton's second law. The net force acting on the system is equal to the product of the mass and acceleration:

Fnet = (20.0 kg + m) * 0.467 m/s²

Since the monkeys are connected by a rope of negligible mass, the tension in the rope is the same for both monkeys. Therefore, the tension in the rope is equal to the net force:

Tension = (20.0 kg + m) * 0.467 m/s²

So, the tension in the rope is (20.0 kg + m) * 0.467 m/s².