Final answer:
The Maclaurin series for f(x) = (1-x)^-2 is the sum of (n+1)x^n from n=0 to infinity, and the associated radius of convergence is 1.
Step-by-step explanation:
The student is asking for the Maclaurin series for the function f(x) = (1-x)^-2 and its radius of convergence. To find the Maclaurin series, we need to look at the pattern that the derivatives of this function follow when evaluated at x = 0. The n-th derivative of f(x) at x = 0 is given by f(n)(0) = n!(n+1). Thus, the Maclaurin series for this function can be expressed as:
Summation from n=0 to infinity of (n!(n+1)x^n) / n!
which simplifies to:
Summation from n=0 to infinity of (n+1)x^n
The radius of convergence for this series can be found using the Ratio Test, which implies that the series converges when the absolute value of x is less than 1, hence the radius of convergence is 1.