Question

Help meeeeeeeeeeeeeeeeeee

Answer 1

`4x√(6x^5)+7x^3√(150) ~~ \begin{cases} x^5=&x^(4+1)\\ &x^4\cdot x^1\\ &x^(2\cdot 2)\cdot x^1\\ &(x^2)^2\cdot x \\\\ 150=&2\cdot 3\cdot 5\cdot 5\\ &6\cdot 5^2 \end{cases} \\\\\\ 4x√(6(x^2)^2\cdot x)+7x^3√(6\cdot 5^2)\implies 4x\cdot x^2√(6x)+7x^3\cdot 5√(6) \\\\\\ 4x^3√(6x)+35x^3√(6)\implies 4x^3√(6)\cdot √(x)+35x^3√(6) \implies \stackrel{\textit{common factoring}}{x^3√(6)( ~~ 4√(x)+35 ~~ )}`