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An air tracker attached to a spring oscillates between 15 cm mark and 65 cm makes on the track. What is the frequency and amplitude

User Casimiro
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Final answer:

The frequency and amplitude of an oscillation can be determined by analyzing the motion of the object. In this case, an air tracker attached to a spring oscillates between the 15 cm and 65 cm marks on the track.

The amplitude of the oscillation is 25 cm and the frequency is 2 Hz.

Step-by-step explanation:

The amplitude of the oscillation is the maximum displacement from the equilibrium position, which is half the difference between the two extreme positions.

Therefore, the amplitude is (65 cm - 15 cm)/2 = 25 cm.

The frequency of the oscillation is the number of cycles completed per unit of time.

To find the frequency, we need to determine the period, which is the time taken to complete one cycle. We can use the formula:

Frequency = 1/Period

Since the air tracker completes one full cycle between the 15 cm and 65 cm marks, we can say that the distance traveled in one full cycle is equal to the wavelength.

Therefore, the period is the time taken to travel the distance of one wavelength.

The wavelength is (65 cm - 15 cm) = 50 cm.

Now, to convert the wavelength from cm to meters, we divide it by 100: 50 cm / 100 = 0.5 m.

Finally, we can calculate the frequency using the formula:

Frequency = 1/Period = 1/0.5

= 2 Hz.

User Charnice
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