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In order to produce CO2, a student put a sample of calcium carbonate in a flask and added hydrochloric acid using the following equation: Ca(CO3) + HCl → H2O + CO2 + CaCl2 The student finds the mass of CO2 generated to be 100 g. If the student began with 200 g of HCl and there was ample CaCO3 left unreacted, what was the percent yield?

User Daniel
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1 Answer

8 votes

Answer:

82.9% Is the percent yield

Step-by-step explanation:

First, we need to balance the equation.

Ca(CO3) + 2HCl → H2O + CO2 + CaCl2

Since the problem tells you that the excess reactant is Ca(CO3), we just need to Stoichiometry to solve for the theoretical yield.


(200g HCl)/(1) x
(1 mole HCl)/(36.46gHCl) x
(1 mol CO2)/(2molHCl) x
(44.01CO2)/(1molCO2) =120.707 g (theoretical yield)

Take your actual yield of 100g, divide that by 120.707, then multiply that decimical by 100.

User Takim
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