Question

How many moles of Agl will be formed when 75.0 mL of 0.300 M AgNO, is

completely reacted according to the balanced chemical reaction:
2 AgNO3(aq) + Cal₂(aq)
-
2 Agl(s) + Ca(NO3)2(aq)

PLEASE ANSWER IN THE SAME FORMAT I already KNOW THE ANSWER BUT MY FORMAT IS WRONG. I have attached a picture

Answer 1

To calculate the number of moles of AgI formed, use the formula Moles = concentration × volume (in liters). Substitute the given values into the formula and consider the balanced chemical equation to determine the number of moles of AgI formed.

In order to determine the number of moles of AgI formed, we first need to calculate the number of moles of AgNO3 that reacted. We can use the formula:

Moles = concentration × volume (in liters)

Given that the concentration of AgNO3 is 0.300 M and the volume is 75.0 mL (which is equivalent to 0.0750 L), we can substitute these values into the formula:

Moles of AgNO3 = 0.300 M × 0.0750 L = 0.0225 moles

According to the balanced chemical equation, the ratio between AgNO3 and AgI is 2:2. Therefore, the number of moles of AgI formed is also 0.0225 moles.