Question

A party mix is made by adding nuts that sell for $2.50 per kg to a cereal that sells for per kgHow much of each should be added to 70 kg of a mix will sell for $1.90 per kg?

Answer 1

The student's question asks for the quantities of nuts and cereal needed to create a 70 kg party mix to be sold at a specific price, using algebraic equations. However, the lack of the cereal's cost per kg prevents us from solving the problem.

Step-by-step explanation:

The question involves creating a mix of two different items: nuts and cereal, to achieve a specified selling price for the mixture. To solve this problem, we will use a system of linear equations to find the quantities of nuts and cereal needed.

Let x be the amount of nuts needed at $2.50 per kg, and y be the amount of cereal needed at an unspecified cost per kg. The goal is a 70 kg party mix that will sell for $1.90 per kg. We have two equations:

1. The total weight of the mix: x + y = 70
2. The total cost of the mix: 2.50x + price of cerealy = 70 * $1.90

However, since the question does not provide the price per kg of the cereal, we cannot compute exact amounts without this information. Hence, we would need that crucial missing piece of data to proceed with the calculations.