The final velocity of the car when it moved from the top mountain to the bottom of the mountain is 243 m/s.
How to calculate the final velocity of the car?
The final velocity of the car when it moved from the top mountain to the bottom of the mountain is calculated as follows;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √ (2gh)
where;
- g is acceleration due to gravity
- h is the height of fall of the car
The final velocity of the car when it moved from the top mountain to the bottom of the mountain is calculated as;
v = √ (2 x 9.8 x 3,000)
v = 242.5 m/s
v = 243 m/s
The complete question is below:
(A car of mass 1,000 kg begins stationary on a road at the top of a mountain, at a height h = 3,000 m. The car then rolls freely down a winding road, traveling a total distance of 5 km, to reach the height h = 2,000 m. Assume g = 9.8 ms-2)
The car continues to roll down the mountain, where it reaches the bottom. Here the height h = 0 m. Assuming no further energy is lost and all the GPE from the top of the mountain is transformed into KE, what is the final velocity of the car? Give your answer to 3 significant figures. Final velocity