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Customer comes in and buys $10 worth of gas and $15.48 in merchandise and gives you a $50 bill. How much of each denomination? $20- _0_; $10- _1_; $5- _2_; $1- _4_; $0.25- _2_; $0.10- _0_; $0.05- _0_; $0.01-_2_ $20- _0_; $10- _2_; $5- _0_; $1- _4_; $0.25- _2_; $0.10- _0_; $0.05- _0_; $0.01-_2_ $20- _1_; $10- _0_; $5- _0_; $1- _4_; $0.25- _2_; $0.10- _0_; $0.05- _0_; $0.01-_2_

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The amount of each denomination the customer receives are;

$20 One

$1 Four

$0.25 Two

$0.01 Two

The number of each of the denomination the customer receives are found as follows;

Customer comes in and buys $10 worth of gas and $15.48 in merchandise, and gives you a $50 bill.

Therefore the amount of change the customer will receive can be found from the difference between the amount the customer presents and the total amount of items purchased

The total amount of items purchased is; $10 + $15.48 = $25.48

The amount to be received by the customer as change is; $50 - $25.48 = $24.52

Therefore, we get; The combination of each denomination the customer may receive are;

$20 One

$10

$5

$1 Four

25¢ which is $0.25 Two

10¢ which is $0.10

5¢ which is $0.05

1¢ which is $0.01 Two

User Jimbo James
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