Answer:
The equation of a circle in standard form is given by \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center of the circle, and \(r\) is the radius.
For the given circle \(2x^2 + 2y^2 - 8x + 12y - 1 = 0\), complete the square to find the standard form. Then, identify the center \((h, k)\) and the radius \(r\).
Once you have the center and radius of the original circle, the concentric circle with double the radius will have its equation as \((x - h)^2 + (y - k)^2 = (2r)^2\).
Without the completed square form of the given circle, I can't provide specific values, but the general process involves completing the square to find the center and radius.