Question

20g of calcium carbonate was heated vigorously to produce calcium oxide and carbon dioxide. calculate the percentage of the decomposition if the volume of carbon dioxide obtained at STP is 4dm ?

Answer 1

To calculate the percentage of decomposition of calcium carbonate, we need to determine the amount of carbon dioxide produced and the initial mass of calcium carbonate. From the given data, we know that 20g of calcium carbonate was heated to produce carbon dioxide. Using stoichiometry, the percentage of decomposition can be calculated as 45.47%.

Step-by-step explanation:

CaCO3 → CaO + CO2

Molar mass of CaCO3: 40.08 g/mol
Molar mass of CO2: 44.01 g/mol

Using the molar mass, we can calculate the moles of CO2 produced:
moles of CO2 = mass of CO2 / molar mass of CO2

moles of CO2 = 4 g / 44.01 g/mol
moles of CO2 = 0.09087 mol

Now, we can calculate the percentage of decomposition:
percentage decomposition = (moles of CO2 / moles of CaCO3) * 100

moles of CaCO3 = 20 g / 100.09 g/mol
moles of CaCO3 = 0.1999 mol

percentage decomposition = (0.09087 mol / 0.1999 mol) * 100
percentage decomposition = 45.47%