Final answer:
After calculating the mass of nitrogen in each compound, 1.5 moles of (NH4)3PO4 contains the greatest mass of nitrogen, amounting to 63.05 grams.
Step-by-step explanation:
To determine which compound contains the greatest mass of nitrogen, we calculate the total mass of nitrogen in each option provided. The molar mass of nitrogen (N) is 14.01 g/mol.
- (NH4)2SO4 contains 2 moles of NH4 (each with one nitrogen), so 0.5 moles of (NH4)2SO4 would contain 1 mole of nitrogen, which would have a mass of 14.01 g.
- NH4NO3 contains 2 moles of nitrogen, so 1 mole of NH4NO3 would have a nitrogen mass of 28.02 g.
- (NH4)3PO4 contains 3 moles of NH4 (each with one nitrogen), so 1.5 moles of (NH4)3PO4 would contain 4.5 moles of nitrogen, which would have a mass of 63.05 g.
- CO(NH2)2 (urea) contains 2 moles of nitrogen, so 2 moles of urea would contain 4 moles of nitrogen, with a total mass of 56.04 g.
Therefore, the compound from the options given that contains the greatest mass of nitrogen is 1.5 moles of (NH4)3PO4.