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Answer:
f(x) = 3(2x + 320/x) + 15(320/x)
f'(x) = 3(2 - 320/x²) - 15(320/x²) = 0
6 - 24(320/x²) = 0
24(320/x²) = 6
320/x² = 1/4
x² = 1,280
x = 16√5, 320/x = 20/√5 = 4√5
The dimensions should be 16√5 ft by 4√5 ft (about 35.78 ft by 8.94 ft).
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