Question

33. A ball of mass m = 8 kg is suspended from a string of length L = 5 m. The ball revolves with speed in a horizontal circle of radius r = 3 m. Calculate the speed. 2.9 m/s a. b. 3.7 m/s c. 4.7 m/s d. 5.7 m/s​

Answer 1

To calculate the speed of the ball, we can use the formula for the centripetal force. By equating the tension in the string to the weight of the ball, we can solve for the speed. The speed of the ball is approximately 5.7 m/s.

Step-by-step explanation:

To calculate the speed of the ball, we can use the formula for the centripetal force:

F = m * v^2 / r

Where F is the tension in the string, m is the mass of the ball, v is the speed, and r is the radius of the circular path. Since the ball is in equilibrium, the tension in the string is equal to the weight of the ball:

T = mg

By equating these two equations, we can solve for the speed:

mg = m * v^2 / r

v^2 / r = g

v^2 = g * r

v = sqrt(g * r)

Plugging in the given values:

v = sqrt(9.8 m/s^2 * 3 m) ≈ 5.7 m/s