Answer:
see explanation
Explanation:
Q1
given line L has equation
y + 2x = 12 ( subtract 2x from both sides )
y = 12 - 2x → (1)
given curve C has equation
y = x² - 4x + 9 → (2)
substitute y = x² - 4x + 9 into (1)
x² - 4x + 9 = 12 - 2x ( add 2x to both sides )
x² - 2x + 9 = 12 ( subtract 12 from both sides )
x² - 2x - 3 = 0 ← equation for x- coordinates
Q2
to find the x- coordinates of the points of intersection, solve the equation
x² - 2x - 3 = 0 ← in standard form
(x - 3)(x + 1) = 0 ← in factored form
equate each factor to zero and solve for x
x - 3 = 0 ⇒ x = 3
x + 1 = 0 ⇒ x = - 1
substitute these values into (1) for corresponding values of y
x = 3 : y = 12 - 2(3) = 12 - 6 = 6 ⇒ (3, 6 )
x = - 1 : y = 12 - 2(- 1) = 12 + 2 = 14 ⇒ (- 1, 14 )
points of intersection are (- 1, 14 ) and (3, 6 )