The probability distribution table shows that the probability of each outcome, 2, 3, or 4, is 1/3.
The probability distribution table shows the probability that two spinners shuffled into a circle at a speed of 1/2, 1/3, and 1/4, shown below. Let the random variable T represent the sum of the two spinners. The probability that two spinners shuffled into a circle at a speed of 1/2, 1/3, and 1/4, shown below.
[Image of a table with the following values:
t | P(t)
-- | --
2 | 1/3
3 | 1/3
4 | 1/3]
The table shows that the probability of each outcome, 2, 3, or 4, is 1/3. This is because there are 3 equally likely outcomes for each spinner, and the sum of the two spinners is 2, 3, or 4.
For example, the probability of getting a sum of 2 is 1/3 because there are 3 equally likely outcomes for each spinner, and only one of those outcomes results in a sum of 2 (that is, if the first spinner lands on 1 and the second spinner lands on 1).
Similarly, the probability of getting a sum of 3 is 1/3 because there are 3 equally likely outcomes for each spinner, and only one of those outcomes results in a sum of 3 (that is, if the first spinner lands on 2 and the second spinner lands on 1, or if the first spinner lands on 1 and the second spinner lands on 2).
The probability of getting a sum of 4 is also 1/3 because there are 3 equally likely outcomes for each spinner, and only one of those outcomes results in a sum of 4 (that is, if the first spinner lands on 2 and the second spinner lands on 2).