Question

Determine if the values of the variables listed are solutions of the system of equations.

4x
+
2z = 26
5y-
BY
-X - 3y +
x = 4, y = -3, z = 5; (4, -3,5)
Z
= -20
4z = 25
Is (4, -3,5) a solution of the system of equations?
A. No, the solution does not satisfy 4x + 2z = 26.
B. No, the solution does not satisfy either 5y-z= -20or -x-3y + 4z = 25.
OC. No, the solution does not satisfy -x-3y + 4z = 25.
D. No, the solution does not satisfy 5y-z= -20.
E. No, the solution does not satisfy either 4x + 2z = 26 or 5y-z= -20.
OF. No, the solutions does not satisfy any of the equations.
OG. Yes, this is a solution to the system of equations.
OH. No, the solution does not satisfy either 4x + 2z = 26 or -x-3y + 4z = 25.

Answer 1

After substituting x=4, y=-3, and z=5 into the given equations, we find that each equation holds true. Therefore, the values (4, -3, 5) are solutions to the system of equations.

Step-by-step explanation:

To determine if the given set of values ((4, -3, 5)) is a solution to the system of equations, we must substitute x=4, y=-3, and z=5 into each equation and see if they satisfy all the equations. Starting with the first equation 4x + 2z = 26, when we substitute the values we get:

• 4(4) + 2(5) = 16 + 10 = 26, which is true.

For the second equation 5y - z = -20, substituting the values gives:

• 5(-3) - 5 = -15 - 5 = -20, which is also true.

Finally, for the third equation -x - 3y + 4z = 25:

• -4 - 3(-3) + 4(5) = -4 + 9 + 20 = 25, this holds true as well.

Since all three equations are satisfied by the given values, the answer to the question is Yes, the values (4, -3, 5) are indeed solutions to the system of equations.