Question

A series circuit consists of a 24 V battery, 47 Ohm resistor, 27 ohm resistor, and 36 Ohm resistor. What is the current flow through the 47 Ohm resistor?

Answer 1

The current through the 47 Ohm resistor in a series circuit with a total resistance of 110 Ohms and a 24 V battery is 0.21818 A.

Step-by-step explanation:

To calculate the current through the 47 Ohm resistor in a series circuit, we first need to find the total resistance of the circuit. We add up the resistances of the individual resistors since they are in series:

• 
  
• 47 Ω (Ohms) resistor
• 
  
• 27 Ω resistor
• 
  
• 36 Ω resistor

Total resistance, Rtotal = 47 Ω + 27 Ω + 36 Ω = 110 Ω.

Next, using Ohm's Law (V = IR), where V is the voltage, I is the current, and R is the resistance, we can find the total current in the circuit:

V = 24 V (voltage of the battery)

Rtotal = 110 Ω (total resistance)

I = V / Rtotal

I = 24 V / 110 Ω

I = 0.21818 A (Amperes)

Since the circuit is a series circuit, the current is the same through all components. Therefore, the current through the 47 Ohm resistor is 0.21818 A.