Question

Calculate the value of two equal charge force each other with a in if they repel of 0. IN when placed 50cm apart vacuum. What would be the distance between them if they placed in an insulating medium dielectric constant 10​

Answer 1

The electrostatic force between two equal charges can be calculated using Coulomb's law. The distance between the charges when placed in an insulating medium can be determined by rearranging the formula for force and solving for 'r'. The distance is found to be 5 cm.

Step-by-step explanation:

The electrostatic force between two charges can be calculated using Coulomb's law formula:
`F = k × (q1 × q2) / r^2`, where F is the force, k is the proportionality constant, q1 and q2 are the charges, and r is the distance between the charges.

In this case, since the two charges are equal and have a value of 'a', the force can be calculated as:
`F = k × (a × a) / r^2.` The force of repulsion is given as 0.N. By substituting this value into the formula, we get:

`0.N = k × (a^2) / (0.5)^2, where \\k = 9 × 10^9 Nm^2/C^2.`

Now, let's calculate the distance between the charges when placed in the insulating medium. The formula for the force in this case is:

F = k × (a × a) / (k × 10), since the dielectric constant is given as 10.

By rearranging the formula and solving for 'r', we find that the distance between the charges when placed in the insulating medium is 5 cm.