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2 out 20 people are heterozygous for the recessive allele for albinism. What would incident of albinism be in population?

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The incident of albinism in the population would be 10%.

Step-by-step explanation:

The incident of albinism in a population can be calculated using the Hardy-Weinberg formula. The formula is p² + 2pq, where p represents the frequency of the dominant allele and q represents the frequency of the recessive allele. In this case, the frequency of the recessive allele can be calculated by taking the square root of the fraction of heterozygous individuals, which is 2 out of 20 or 0.1. Therefore, q = √0.1 = 0.316.

Since the recessive allele is homozygous recessive for albinism, q² would represent the incident of albinism in the population. Applying the formula, q² = (0.316)² = 0.1.

Therefore, the incident of albinism in the population would be 0.1 or 10%.