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College students’ weights (in lbs.) have a normal distribution with mean = 60 and standard deviation = 3. Suppose that 42 students are sampled at random from this population.What is the probability that the sample mean of the weights of 42 students is between 58 and 61 lbs.

User Zooko
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The probability that the sample mean of weights is between 58 and 61 lbs is approximately 0.0857 or 8.57%.

Sample mean distribution: Since we're sampling from a normally distributed population with a large sample size (42), the central limit theorem applies. This means the distribution of the sample means will also be normal, with:

Mean = Population mean = 60 lbs.

Standard deviation = Population SD / sqrt(sample size) = 3 lbs / sqrt(42) = 0.44 lbs.

Finding the desired probability: We want the probability that the sample mean falls between 58 and 61 lbs. This corresponds to a range of one standard deviation (0.44 lbs) on either side of the population mean (60 lbs).

Z-scores and the standard normal table: We can use Z-scores to calculate this probability. Z-scores represent how many standard deviations a specific value is away from the mean. For our desired range, the Z-scores are:

Lower limit: (58 lbs - 60 lbs) / 0.44 lbs = -0.45

Upper limit: (61 lbs - 60 lbs) / 0.44 lbs = 0.23

Consulting the standard normal table: This table gives the probability of a standard normal variable falling below a certain Z-score. We can use it twice:

Find the probability below -0.45 (lower limit): 0.6760

Find the probability below 0.23 (upper limit): 0.5917

Final probability calculation: The probability that the sample mean falls between 58 and 61 lbs is the difference between these two probabilities: 0.5917 - 0.6760 = 0.0857.

User Micfra
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