Question

A boulder rolls down a hill and launches off a cliff with an initial velocity of 3 m/s. The height of the cliff is 32 m. What is the horizontal displacement of the boulder when it hits the ground?

Answer 1

Answer: 7.67m

Step-by-step explanation:

Initial velocity X direction: 3 m/s

Initial velocity Y direction: 0 m/s

X Displacement: (?)

Y Displacement: -32 m

X acceleration: 0

Y acceleration: -9.8 m/s^2

Time to hit ground: (?)

X displacement= (X velocity)(time)

Use Y values to solve for time using kinematics:

t= sqrt(2* Displacement Y/ Acceleration Y)

t= sqrt (2*-32m/-9.8ms2)

t= 2.55 m/s

Use found t value in X displacement equation.

=(x velocity)(time)

=(3 m/s)(2.55m)

=7.67 m