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Given the circle below with secants GHI and KJI. If HI=15, JI=13 and GH is less than KJ, find the length of KJ. Round to the nearest tenth if necessary.

User Stefan Luv
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To determine the length of KJ, we can use the Pythagorean theorem and substitute the given values into the equation.

The length of HJ is 15 units and the length of JI is 13 units. Since GH is shorter than KJ, we can determine the length of KJ by finding the length of GH. To find GH, we can use the Pythagorean theorem, which says that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the lengths of the other two sides. In this case, the hypotenuse is KJ and the other two sides are GH and HI. So we have:

KJ^2 = GH^2 + HI^2

Since we know the lengths of HJ and JI, we can substitute them into the equation:

KJ^2 = GH^2 + (HJ + JI)^2

Substituting the given values:

KJ^2 = GH^2 + 15^2 + 13^2

Since GH is shorter than KJ, we can conclude that the length of KJ is greater than the length of GH. However, without any additional information, we cannot determine the specific length of KJ.

The probable question may be:

In a magical garden, there is a mystical circle, and two enchanted paths, GHI and KJI, are drawn on it. If the length of HJ is 15 and JI is 13, and we know that GH is shorter than KJ, can you determine the length of KJ?

Additional Information:

Imagine wandering through a captivating garden filled with colorful flowers and ancient trees. In this magical place, two paths, GHI and KJI, cross the enchanted circle. The mystical circle holds secrets, and the paths weave through the garden's wonders. The length of HJ, a portion of the path GHI, is 15 units, and the length of JI is 13 units. Given this, can you unveil the magical length of KJ, the other path, as you continue your journey through the enchanting garden?

User Mosceo
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