Answer: False
Step-by-step explanation
There are n = 3 coins and 2^n = 2^3 = 8 different outcomes of heads (H) or tails (T)
Here is the sample space. This is the list of all possible outcomes.
- HHH
- HHT
- HTH
- THH
- HTT
- THT
- TTH
- TTT
The binary number system can be helpful to generate that list above.
The event "no heads appear" is the same as the event "3 tails". That has probability of 1/8 since there is one TTT out of 8 items total.
The event "exactly 1 head appears" has probability 3/8 since we have the items HHT and HTH and THH.
The probabilities 1/8 and 3/8 do not match up. The events "No heads appear" and "Exactly 1 Head appears" are not equally likely. The original claim is false