Question

Find the slope of a line perpendicular to the line whose equation is 3, x, minus, 3, y, equals, 3x−3y=63. Fully simplify your answer

Answer 1

-1

Explanation:

First, convert 3x - 3y = 63 into slope y-intercept form.

3x - 3y = 63
-3y = -3x + 63

Divide by -3 to isolate y.

y = x - 21

The slope is the coefficient on x. In this case, it's one. For lines to be perpendicular, their slopes must be negative reciprocals.

Negative reciprocals = two numbers that multiply to negative one.

So, let m represent the slope of the perpendicular line.

1m = -1 --> this equation will get us the negative reciprocal

m = -1

Therefore the slope of the perpendicular line is m = -1.