Final answer:
The preimage of C'(2, -4) can be found by substituting the components into the given equation. The preimage is (√(69/9), √(69/9)).
Step-by-step explanation:
The preimage of C'(2, -4) can be found using the given components Cx = -2/3, Cy = -4/3, and C₂ = 7/3.
Substituting these values into Equation 2.21, we can solve for the preimage.
Using the equation C = √(Cx² + Cy² + C₂²), we get C = √((-2/3)² + (-4/3)² + (7/3)²) = √(4/9 + 16/9 + 49/9) = √(69/9).
Therefore, the preimage of C'(2, -4) is (√(69/9), √(69/9)).