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Answer 1

Check the picture below.

`\stackrel{\textit{area of the poster}}{3~ft * 3~ft}\implies 9~ft^2 \\\\\\ \stackrel{\textit{volume of the box}}{\sqrt[3]{30}* \sqrt[3]{30}* \sqrt[3]{30}}\implies \sqrt[3]{30* 30* 30}\implies \sqrt[3]{30^3}\implies 30~ft^3 \\\\\\ \textit{each side of the box is }\sqrt[3]{30}\approx 3.11~ft\qquad \textit{so the poster lies flat inside it}`