Final answer:
The temperature of 259g of water would increase by approximately 33.5°C when 36.0 kJ of heat is added, calculated using the formula q = mcΔT with the specific heat capacity of water.
Step-by-step explanation:
To calculate the increase in temperature for a specific mass of water when a certain amount of heat is added, we use the formula q = mcΔT, where q is the heat added in Joules, m is the mass of the water in grams, c is the specific heat capacity (4.184 J/g°C for water), and ΔT is the change in temperature in °C.
Given that 36.0 kJ (or 36000 J) of heat is added to 259 g of water at 25°C, we can rearrange the formula to solve for ΔT: ΔT = q / (mc).
ΔT = (36000 J) / (259 g × 4.184 J/g°C)
ΔT ≈ 33.5°C (rounded to one decimal place)
Therefore, the temperature of the 259 g of water would increase by approximately 33.5°C when 36.0 kJ of heat is added.