Final answer:
To determine the capacity of the large fishbowl, multiply the small fishbowl's capacity of 2 2/5 gallons by 2 1/3, resulting in the large fishbowl holding 5 3/5 gallons of water.
Step-by-step explanation:
To find out how many gallons the large fishbowl holds, we need to multiply the capacity of the small fishbowl by 2 1/3. First, let's convert the mixed numbers to improper fractions to make the multiplication easier. The small fishbowl holds 2 2/5 gallons, which can be converted to an improper fraction: 2 2/5 = (2×5) + 2 = 10/5 + 2/5 = 12/5 gallons.
Now, we need to multiply this by 2 1/3 times. Convert 2 1/3 to an improper fraction as well: 2 1/3 = (2×3) + 1 = 6/3 + 1/3 = 7/3.
Multiplying the two improper fractions we get: (12/5) × (7/3) = 84/15. To simplify this, we divide both the numerator and the denominator by their greatest common divisor, which is 3, getting 28/5. However, this is still an improper fraction. Converting it back to a mixed number, we divide the numerator by the denominator: 28 ÷ 5 = 5 with a remainder of 3. So the large fishbowl holds 5 3/5 gallons of water.