Final answer:
The final concentration of a solution obtained by diluting 5.00 mL of a 48.5 M stock solution to a final volume of 18.0 L is 0.01347 M.
Step-by-step explanation:
To calculate the final concentration after dilution, we can use the equation C1V1 = C2V2, where C1 and V1 represent the concentration and volume of the initial solution, and C2 and V2 represent the concentration and volume of the final solution. In your example, you dilute 5.00 mL (which is 0.005 L) of a 48.5 M stock solution to a final volume of 18.0 L. Using the equation:
C1V1 = C2V2
- C1 = 48.5 M
- V1 = 0.005 L
- V2 = 18.0 L
- C2 = ? (We need to find this)
We rearrange the equation to solve for C2:
C2 = (C1V1) ÷ V2
Substitute the values:
C2 = (48.5 M * 0.005 L) ÷ 18.0 L
Now calculate:
C2 = (0.2425 mol) ÷ 18.0 L
C2 = 0.01347 M
Therefore, the final concentration of the solution after dilution is 0.01347 M.