Question

A total of 11% of students at a large high school are left-handed. A statistics teacher selects a random sample of 100 students

; and records L = the number of left-handed students in the sample.
What is the probability that 15 or more students in the sample are left-handed?

A) 0.867

B)0.0802

C) 0.0528

D) 0.9198

E) 0.133

Answer 1

To find the probability that 15 or more students in the sample are left-handed, use the binomial distribution to calculate the sum of probabilities. The answer is B) 0.0802.

Step-by-step explanation:

To find the probability that 15 or more students in the sample are left-handed, we need to use the binomial distribution.

We know that the probability of selecting a left-handed student is 11% or 0.11.

Using the binomial probability formula:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

where:

P(X = k) is the probability that k students are left-handed,

C(n, k) is the number of combinations of n items taken k at a time,

p is the probability of selecting a left-handed student, and

n is the number of students in the sample.

To find the probability of 15 or more left-handed students, we need to calculate the sum of the probabilities of selecting 15, 16, 17, ..., up to 100 left-handed students.

Using a calculator or software, the probability is approximately 0.0802.

Therefore, the answer is B) 0.0802.