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What would be the volume of a 0.25M solution, containing 12.0 g of NaCl?

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Final answer:

To find the volume of a 0.25M solution containing 12.0 g of NaCl, calculate the moles of NaCl using its molar mass and then use the molarity formula. The result is that the required volume is 0.82 liters.

Step-by-step explanation:

To calculate the volume of a 0.25M solution containing 12.0 g of NaCl, we need to use the formula:

Molarity (M) = moles of solute / volume of solution in liters

First, we calculate the moles of NaCl using the formula:

Moles = mass (g) / molar mass (g/mol)

For NaCl, which has a molar mass of approximately 58.44 g/mol, the number of moles in 12.0g of NaCl is:

Moles of NaCl = 12.0 g / 58.44 g/mol = 0.205 moles

Using the molarity equation to solve for the volume:

Volume of solution in liters = moles of solute / Molarity (M)

Volume of solution = 0.205 moles / 0.25 M = 0.82 liters

Therefore, the volume of a 0.25M NaCl solution containing 12.0 g of NaCl is 0.82 liters.

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