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Use elimination to solve the system of equations:
y+z=4
y-z=8

User Zaknotzach
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To solve the system of equations using elimination, we can add the two equations together to eliminate the variable "z". Adding the equations gives us:

(y + z) + (y - z) = 4 + 8

Simplifying, we get:

2y = 12

Dividing both sides by 2, we find:

y = 6

Now we can substitute the value of "y" back into one of the original equations to solve for "z". Let's use the first equation:

y + z = 4

Substituting y = 6, we have:

6 + z = 4

Solving for "z", we find:

z = -2

Therefore, the solution to the system of equations is y = 6 and z = -2.
User Rockingskier
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