Question

Write the first six terms of the sequence, f(n)

n
4n-2
The first six terms of the sequence are, and

Answer 1

To find the first six terms of the sequence f(n) = 4n - 2, the numbers from 1 to 6 are substituted into the formula, resulting in the terms 2, 6, 10, 14, 18, and 22.

Step-by-step explanation:

To write the first six terms of the sequence represented by f(n) = 4n - 2, we must substitute the values of n from 1 to 6 into the formula.

• 
  
• When n = 1: f(1) = 4(1) - 2 = 2
• 
  
• When n = 2: f(2) = 4(2) - 2 = 6
• 
  
• When n = 3: f(3) = 4(3) - 2 = 10
• 
  
• When n = 4: f(4) = 4(4) - 2 = 14
• 
  
• When n = 5: f(5) = 4(5) - 2 = 18
• 
  
• When n = 6: f(6) = 4(6) - 2 = 22

Therefore, the first six terms of the sequence are 2, 6, 10, 14, 18, and 22.