Question

Solve this with the quadratic formula

Answer 1

x = -3

x = -1

Explanation:

The quadratic formula provides the solutions for the roots of a quadratic equation in the form ax² + bx + c = 0.

`\boxed{\begin{array}{l}\underline{\sf Quadratic\;Formula}\\\\x=(-b \pm √(b^2-4ac))/(2a)\\\\\textsf{when} \;ax^2+bx+c=0 \\\end{array}}`

In the case of x² + 4x + 3 = 0, the coefficients are:

• a = 1
• b = 4
• c = 3

Substitute these values into the quadratic formula:

`x=(-(4) \pm √((4)^2-4(1)(3)))/(2(1))`

Now, solve for x:

`x=(-4 \pm √(16-12))/(2)`

`x=(-4 \pm √(4))/(2)`

`x=(-4 \pm 2)/(2)`

`x=-2\pm1\\`

Therefore, the two solutions are:

`x=-2-1=\boxed{-3}`

`x=-2+1=\boxed{-1}`