Solve this with the quadratic formula

Question

asked Feb 21, 2024 85.6k views

1 Answer

Hlib Derbenov · Answer 1 · 2024-02-27T17:10:23+0000

Answer:

x = -3

x = -1

Explanation:

The quadratic formula provides the solutions for the roots of a quadratic equation in the form ax² + bx + c = 0.

$\boxed{\begin{array}{l}\underline{\sf Quadratic\;Formula}\\\\x=(-b \pm √(b^2-4ac))/(2a)\\\\\textsf{when} \;ax^2+bx+c=0 \\\end{array}}$

In the case of x² + 4x + 3 = 0, the coefficients are:

Substitute these values into the quadratic formula:

$x=(-(4) \pm √((4)^2-4(1)(3)))/(2(1))$

Now, solve for x:

$x=(-4 \pm √(16-12))/(2)$

$x=(-4 \pm √(4))/(2)$

$x=(-4 \pm 2)/(2)$

$x=-2\pm1\\$

Therefore, the two solutions are:

$x=-2-1=\boxed{-3}$

$x=-2+1=\boxed{-1}$