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A vessel contains 5 moles of gas X, 2 moles of gas Y, and 1 mole of gas Z. The total pressure of the mixture 24 atm. Calculate the partial pressure of each gas.

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The partial pressure of gas X is 15 atm, gas Y is 6 atm, and gas Z is 3 atm.

To calculate the partial pressure of each gas in a mixture, you can use Dalton's Law of Partial Pressures. According to Dalton's Law:

\[ P_{\text{total}} = P_X + P_Y + P_Z \]

where \( P_{\text{total}} \) is the total pressure of the mixture, and \( P_X, P_Y, P_Z \) are the partial pressures of gases X, Y, and Z, respectively.

Given that the total pressure (\( P_{\text{total}} \)) is 24 atm and the moles of each gas, you can calculate the partial pressures using the mole fraction of each gas:

\[ P_X = \frac{n_X}{n_{\text{total}}} \times P_{\text{total}} \]

\[ P_Y = \frac{n_Y}{n_{\text{total}}} \times P_{\text{total}} \]

\[ P_Z = \frac{n_Z}{n_{\text{total}}} \times P_{\text{total}} \]

where \( n_X, n_Y, n_Z \) are the moles of gases X, Y, and Z, and \( n_{\text{total}} \) is the total number of moles in the mixture.

Given:

\[ n_X = 5 \, \text{moles} \]

\[ n_Y = 2 \, \text{moles} \]

\[ n_Z = 1 \, \text{mole} \]

\[ n_{\text{total}} = n_X + n_Y + n_Z = 5 + 2 + 1 = 8 \, \text{moles} \]

Calculate partial pressures:

\[ P_X = \frac{5}{8} \times 24 \, \text{atm} \]

\[ P_Y = \frac{2}{8} \times 24 \, \text{atm} \]

\[ P_Z = \frac{1}{8} \times 24 \, \text{atm} \]

Now, calculate the values:

\[ P_X = \frac{5}{8} \times 24 \, \text{atm} = 15 \, \text{atm} \]

\[ P_Y = \frac{2}{8} \times 24 \, \text{atm} = 6 \, \text{atm} \]

\[ P_Z = \frac{1}{8} \times 24 \, \text{atm} = 3 \, \text{atm} \]

Therefore, the partial pressure of gas X is 15 atm, gas Y is 6 atm, and gas Z is 3 atm.

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