Question

Determine the molar mass of Mn(C103) 4.

Answer 1

The molar mass of
`Mn(ClO_3)_4`is 388.74 g/mol.

Step-by-step explanation:

The molar mass of
`Mn(ClO_3)_4` can be calculated by adding up the atomic masses of manganese (Mn), chlorine (Cl), and oxygen (O). The molar mass of
`Mn(ClO_3)_4` is:

1 mol of Mn = 54.94 g/mol

4 mol of Cl = 4 x 35.45 g/mol = 141.8 g/mol

12 mol of O = 12 x 16.00 g/mol = 192 g/mol

Therefore, the molar mass of
`Mn(ClO_3)_4`is 54.94 g/mol + 141.8 g/mol + 192 g/mol = 388.74 g/mol.