Question

2. A hamburger has twice as many calories as a bowl of soup. Together they have 738 calories. How many calories are in each?

Answer 1

The bowl of soup has 246 calories and the hamburger has 492 calories. The solution is found by setting up a system of equations based on the information that a hamburger has twice as many calories as the bowl of soup and their combined caloric content is 738 calories.

Step-by-step explanation:

A student asked about figuring out the calorie content of a hamburger and soup, given that the hamburger has twice as many calories as the bowl of soup, and together they have a total of 738 calories.

To find the calories in each, we will set up a system of equations.

Step-by-Step Solution:

1. Let ‘h’ represent the number of calories in the hamburger.
2. Let ‘s’ represent the number of calories in the bowl of soup. Given that the hamburger has twice as many calories as the soup, we can express this as h = 2s.
3. The total calories in both the hamburger and soup is 738, which gives us the equation h + s = 738.
4. Substitute the expression for ‘h’ from step 2 into the equation from step 3 to get 2s + s = 738.
5. Combine like terms for ‘s’ to get 3s = 738.
6. Divide both sides by 3 to find s = 246, which is the number of calories in the bowl of soup.
7. Using the relationship from step 2, calculate the number of calories in the hamburger: h = 2s = 2 × 246 = 492.

Therefore, the bowl of soup has 246 calories, and the hamburger has 492 calories.