Question

Given a unit circle, what is the value of

x at the indicated point?
(x, ³).
D
(1,0)
X =
-
√[?]
Hint: The equation
for the unit circle is
x² + y² = 1.
Enter

Answer 1

x = -√7/4

Explanation:

x^2 + y^2 = 1

y = 3/4 at the indicated point, so:

x^ 2 + (3/4)^2 = 1

x^2 + 9/16 = 1

x^2 = 1 - 9/16

x^2 = 7/16

x = +/- √(7/16)

x = +/- √7/4

The x value is to the left of x = 0 so we take the negative value.

x = -√7/4