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(x³-4x+6) divided (x+3)

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To divide (x³-4x+6) by (x+3), use long division. The quotient is -x² + 3x - 15, and the remainder is 27.

To divide (x³-4x+6) by (x+3), we can use long division:

-x² + 3x - 15
---------------------------
x + 3 | x³ - 4x + 6
- (x³ + 3x²)
--------------
-7x + 6
- (-7x - 21)
------------
27

Therefore, the quotient when (x³-4x+6) is divided by (x+3) is -x² + 3x - 15, and the remainder is 27.

User Nikolaus Gradwohl
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