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Solve for the value of Y. Round to the nearest tenth ( 1 decimal place) of necessary.​

Solve for the value of Y. Round to the nearest tenth ( 1 decimal place) of necessary-example-1

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The value of y, the base in a right-angled triangle with a 45-degree angle, a height of
\(3√(2)\), and a hypotenuse x, is approximately 4.2 (rounded to the nearest tenth).

In a right-angled triangle with a 45-degree angle, the sides are related by the properties of a 45-45-90 triangle. The ratio of the sides is
\(1:1:√(2)\).

Given that the height is
\(3√(2)\) and the hypotenuse is (x), the base (y) can be found using the ratio:


\[ \text{Height} : \text{Base} : \text{Hypotenuse} = 1 : 1 : √(2) \]

So, we have:


\[ 3√(2) : y : x = 1 : 1 : √(2) \]

Now, solve for y:


\[ y = 3√(2) * 1 = 3√(2) \]

Therefore, the value of y is
\(3√(2)\), rounded to the nearest tenth.

User Chris Mack
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