152k views
0 votes
Y=-8\left(2\right)^{x}

User DkAngelito
by
8.0k points

1 Answer

6 votes

When substituting -32 for y in the given exponential function, solving for x results in x = 2. This implies that when y is -32, the exponential function is satisfied when x is 2.

To determine the value of x when y is -32 in the exponential function y = -8 * 2^x, we substitute -32 for y in the equation and solve for x:

-32 = -8 * 2^x

Dividing both sides by -8 to isolate the exponential term, we get:

4 = 2^x

Recognizing that 4 is equivalent to 2^2, we find that x must be 2. This is because any number raised to the power of 2 results in 4.

So, in the exponential function y = -8 * 2^x, when y is -32, the corresponding value of x is 2.

The question probable may be;

What is the value of x when y is -32 in the exponential function y = -8 * 2^x?

User Jeconom
by
8.6k points