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Trevor buys four and three-eighths pounds of corn and three and seven-twelfths pounds of squash. How many pounds does he purchase in all? seven and four-twelfths pounds seven and ten-twentieths pounds seven and twenty-three twenty-fourths pounds eight and one twenty-fourth pounds

User Puzz
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Final answer:

Trevor buys a total of 7 and 23/24 pounds of corn and squash combined by adding the weight of both the items after converting their fractions to a common denominator. Therefore correct option is C

Step-by-step explanation:

To solve how many pounds Trevor purchases in all, you need to add the weights of the corn and the squash together:

  • Four and three-eighths pounds (4 3/8 lbs) of corn
  • Three and seven-twelfths pounds (3 7/12 lbs) of squash

First, we will convert the fractions to have the same denominator to be able to add them easily:

3/8 is the same as 9/24 (multiply both the numerator and the denominator by 3),

7/12 is the same as 14/24 (multiply both the numerator and the denominator by 2).

Now, let's add the whole numbers and the fractions separately:

4 + 3 = 7 pounds

9/24 + 14/24 = 23/24 pounds

Therefore, when we add these together:

7 pounds + 23/24 pounds = 7 and 23/24 pounds

Trevor buys a total of 7 and 23/24 pounds of corn and squash.

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Trevor buys four and three-eighths pounds of corn and three and seven-twelfths pounds of squash. How many pounds does he purchase in all?

A)seven and four-twelfths pounds B) seven and ten-twentieths pounds

C)seven and twenty-three twenty-fourths pounds D) eight and one twenty-fourth pounds

User Amityo
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