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Given BC||DE and AD = 15, DB = 12,
and AE = 10. Find EC.

Given BC||DE and AD = 15, DB = 12, and AE = 10. Find EC.-example-1
User Apascual
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1 Answer

7 votes

The value of length EC is 8

Similar triangles are triangles with equal corresponding angles and equal side ratio. What this means is that the ratio of the corresponding sides are equal.

Since DE is parallel to BC, the triangles ABC and ADE are similar.

let EC be x

15/27 = 10/10+x

15(10+x ) = 27 × 10

150 + 15x = 270

15x = 270 - 150

15x = 120

divide both sides by 15

x = 120/15

x = 8

Therefore the value of EC is 8

User Homap
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