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Solve the triangle using pythagorean theorm and sides given

Solve the triangle using pythagorean theorm and sides given-example-1

2 Answers

5 votes

Answer:

FH:

we can't use pythagoras, we apply

sin46°=HF/GF

sin46=HF/8.3

HF = sin(46)*8.3=5.97...=6 (rounded)

GH :

GHF rectangular in H

we know GFand HF, pythagoras

GF²=GH²+HF²

8.3²=HG²+6²

HG²=8.3²-6²

HG= √32.84≈5.73...≈5.7

∠F:

the sum of the angles of a triangle =180°.

we know H and G

F =180°-90°-46°=44°

Explanation:

User Sven Schoenung
by
8.3k points
6 votes


\(c=2184.89\)

Explanation:


a^2 +b^2=c^2


46^2+8.3^2=c^2


2116+68.89=c^2


2184.89=c^2


√(2184.89) =√(c)


\(c=2184.89\)

User Sajjan Gurung
by
8.0k points